3^x-1=(1/27)^2x-1

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Solution for 3^x-1=(1/27)^2x-1 equation: 



3^x-1=(1/27)^2x-1

We move all terms to the left:

3^x-1-((1/27)^2x-1)=0



Domain of the equation: 27)^2x-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3^x-((+1/27)^2x-1)-1=0

We multiply all the terms by the denominator


3^x*27)^2x-1)-((-1*27)^2x-1)+1=0

We add all the numbers together, and all the variables

3^x*27)^2x-1)-((-27)^2x-1)+1=0

Wy multiply elements

81x^2-27)^2x-1)+1=0

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